woot im back.

to my split personality and faithful readers, here's my take on why its half.

Based on the assumption that the host has no prior knowledge of what is behind each door (i.e. he does NOT know where the car is), and discounting the scenario where he opens the door with the car, i argue that the probability for the contestant now switches to half.

Since the host does not know where the car is, by opening one door, he is effectively resetting the problem for the contestant - one that has only has two options instead of three. Consider this, in the original Monty Hall problem, there is a 2:1 ratio of scenarios whereby the host opens door B in favour of switching. But in this variant, it is a 1:1 ratio.

I know this isn't the most convincing of answers, i've still yet to find out figure out how the host's knowledge (or lack of) affects the problem, but i do know (intuitively) that it has something to do with the ratio of scenarios. I understand that this "variant" is rather far-fetched, as it discounts the probability that the host opens the door with the car (1/3 chance!!), hence it is rather lacking still..
I'll be back with more substantial reasoning, dont worry.


On a lighter note, im back!! Yes i know i've been MIA for a long while, many thanks to my split personality who has almost staked a claim for full ownership of this blog. i've been doing alright in the land of the conscripts, enjoying (or rather, trying to) National Slavery. No matter, 13 more months and im gone.